二叉树的层序遍历 II
题目介绍
给定一个二叉树,返回其节点值自底向上的层序遍历。 (即按从叶子节点所在层到根节点所在的层,逐层从左向右遍历)
例如:
给定二叉树 [3,9,20,null,null,15,7],
返回其自底向上的层序遍历为:
题目解法
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72
| package algorithm;
import java.util.LinkedList; import java.util.List; import java.util.Queue;
public class BinaryTreeLevelOrderTraversalII {
public static List<List<Integer>> levelOrderBottom(TreeNode root) {
List<List<Integer>> ans = new LinkedList<>(); if (root == null) { return ans; } Queue<TreeNode> queue = new LinkedList<>(); queue.offer(root);
while (!queue.isEmpty()) { List<Integer> temp = new LinkedList<>(); int size = queue.size(); for (int i = 0; i < size; i++) { TreeNode node = queue.poll(); temp.add(node.val);
if (node.left != null) { queue.offer(node.left); } if (node.right != null) { queue.offer(node.right); } } ans.add(0, new LinkedList<>(temp)); }
return ans; }
public static void main(String[] args) { TreeNode n1 = new TreeNode(3); TreeNode n2 = new TreeNode(9); n1.left = n2; TreeNode n3 = new TreeNode(20); n1.right = n3; TreeNode n4 = new TreeNode(15); n2.left = null; n2.right = null; n3.left = n4; TreeNode n5 = new TreeNode(7); n3.right = n5;
levelOrderBottom(n1); }
public static class TreeNode { int val; TreeNode left; TreeNode right;
TreeNode() { }
TreeNode(int val) { this.val = val; }
TreeNode(int val, TreeNode left, TreeNode right) { this.val = val; this.left = left; this.right = right; } } }
|
打印:
思路:
思路上,其实和z字形很类似。只不过借助于java的api实现头插入。以后可以试试Go或者C的写法。